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Happy birthday steve jobs...

S

spencerb

Guest
MacAddikt said:
not exactly 100% probable:

set A to "no one in group has same birthday"
set Ac to "at least 2 people have same bday"

P(A) = 365!/[(365-60)!(365^60)] = .5877%

so the not probability of A, or Ac = 1-P(A) = 99.4%

easy to find minimum for 100% probability, replace 60 with a variable, x, and solve for x.
Click to expand...
Eh, I was close enough. lol I should have said "it's virtually certain" or something like that. My point is that it doesn't take a large group. I did get to observe this once. I was in a group of 50-60 people, and we were lining up in order of our birthdays, and two people said "our birthday is the same!"
 

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